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(N/A) $(i)$ Clearly,the distance of point $P$ from the $y$-axis is $3$ units and its distance from the $x$-axis is $2$ units. Since $P$ lies in the fi

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(N/A) $(i)$ Clearly,the distance of point $P$ from the $y$-axis is $3$ units and its distance from the $x$-axis is $2$ units. Since $P$ lies in the first quadrant,its coordinates are $(3, 2)$.
Point $R$ lies on the $x$-axis,and its distance from the $y$-axis is $3$ units and from the $x$-axis is $0$ units. So,its coordinates are $(3, 0)$.
Clearly,point $Q$ lies in the fourth quadrant. The distance of $Q$ from the $y$-axis is $3$ units and from the $x$-axis is $1$ unit. So,the coordinates of $Q$ are $(3, -1)$.
$(ii)$ From the given figure,we observe that the points $L$ and $M$ lie on the same vertical line $x = 3$. Therefore,the abscissa (the $x$-coordinate) of both points $L$ and $M$ is $3$.
Hence,the difference between the abscissa of the points $L$ and $M$ is $3 - 3 = 0$.

In the figure,$LM$ is a line parallel to the $y$-axis at a distance of $3$ units.
$(i)$ What are the coordinates of the points $P, R,$ and $Q$?
$(ii)$ What is the difference between the abscissa of the points $L$ and $M$?

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In the figure,$LM$ is a line parallel to the $y$-axis at a distance of $3$ units.$(i)$ What are the coordinates of the points $P, R,$ and $Q$?$(ii)$ What is the difference between the abscissa of the points $L$ and $M$?