In the given figure,$PQ = PR$ and $\angle Q = \angle R$. Prove that $\triangle PQS \cong \triangle PRT$.
(N/A) In $\triangle PQS$ and $\triangle PRT$:
$1$. $PQ = PR$ (Given)
$2$. $\angle Q = \angle R$ (Given)
$3$. $\angle QPS = \angle RPT$ (Common angle $\angle P$)
Therefore,by the $ASA$ (Angle-Side-Angle) congruence criterion,$\triangle PQS \cong \triangle PRT$.
$1$. $PQ = PR$ (Given)
$2$. $\angle Q = \angle R$ (Given)
$3$. $\angle QPS = \angle RPT$ (Common angle $\angle P$)
Therefore,by the $ASA$ (Angle-Side-Angle) congruence criterion,$\triangle PQS \cong \triangle PRT$.
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