In Delta ABC and Delta PQR,angle A cong angle | vedclass

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(C) Given that in $\Delta ABC$ and $\Delta PQR$,$\angle A = \angle P$ and $\angle B = \angle Q$.By the $AA$ (Angle-Angle) similarity criterion,$\Delta

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) Given that in $\Delta ABC$ and $\Delta PQR$,$\angle A = \angle P$ and $\angle B = \angle Q$.By the $AA$ (Angle-Angle) similarity criterion,$\Delta ABC \sim \Delta PQR$.Since the triangles are similar,the ratios of their corresponding sides are equal:$\frac{AB}{PQ} = \frac{AC}{PR} = \frac{BC}{QR}$.We are given $\frac{AB}{PQ} = \frac{4}{5}$ and $AC = 20$.Substituting these values into the ratio:$\frac{4}{5} = \frac{20}{PR}$.Cross-multiplying to solve for $PR$:$4 	imes PR = 5 	imes 20$.$4 	imes PR = 100$.$PR = \frac{100}{4} = 25$.Therefore,the length of $PR$ is $25$.

In $\Delta ABC$ and $\Delta PQR$,$\angle A \cong \angle P$ and $\angle B \cong \angle Q$. If $\frac{AB}{PQ} = \frac{4}{5}$ and $AC = 20$,find $PR$.

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