In Delta ABC,if angle A = angle B + angle C,t | vedclass

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Question

(A) In any triangle $\Delta ABC$,the sum of all interior angles is $180^{\circ}$.Therefore,$\angle A + \angle B + \angle C = 180^{\circ}$.Given that $

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(A) In any triangle $\Delta ABC$,the sum of all interior angles is $180^{\circ}$.Therefore,$\angle A + \angle B + \angle C = 180^{\circ}$.Given that $\angle A = \angle B + \angle C$.Substituting $(\angle B + \angle C)$ with $\angle A$ in the sum equation:$\angle A + (\angle B + \angle C) = 180^{\circ}$$\angle A + \angle A = 180^{\circ}$$2\angle A = 180^{\circ}$$\angle A = \frac{180^{\circ}}{2} = 90^{\circ}$.

In $\Delta ABC$,if $\angle A = \angle B + \angle C$,then $\angle A = \ldots$ (in $^{\circ}$)

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