In Delta ABC and Delta PQR,m angle A = m angl | vedclass

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(B) Given that in $\Delta ABC$ and $\Delta PQR$,we have $m \angle A = m \angle R$ and $m \angle B = m \angle Q$.By the Angle-Angle $(AA)$ similarity c

Vedclass · Accepted Answer

$RQP$

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(B) Given that in $\Delta ABC$ and $\Delta PQR$,we have $m \angle A = m \angle R$ and $m \angle B = m \angle Q$.By the Angle-Angle $(AA)$ similarity criterion,if two angles of one triangle are equal to two angles of another triangle,then the two triangles are similar.The correspondence must match the equal angles in order.Since $\angle A = \angle R$,$\angle B = \angle Q$,and by the angle sum property,$\angle C = \angle P$.Therefore,the correspondence $ABC \leftrightarrow RQP$ is a similarity.

In $\Delta ABC$ and $\Delta PQR$,$m \angle A = m \angle R$ and $m \angle B = m \angle Q$. Then,the correspondence $ABC \leftrightarrow \ldots$ is a similarity.

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