In $\Delta ABC$,$\angle B$ is a right angle. Then,according to Pythagoras' theorem,$\ldots \ldots \ldots$ holds good.

  • A
    $AB^{2} = AC^{2} + BC^{2}$
  • B
    $AC^{2} = AB^{2} + BC^{2}$
  • C
    $BC^{2} = AB^{2} + AC^{2}$
  • D
    $AC^{2} = AB \cdot BC$

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