In the F_{2} generation of a Mendelian dihybr | vedclass

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(D) In a Mendelian dihybrid cross involving two traits,the $F_{2}$ phenotypic ratio is $9:3:3:1$.
Total number of combinations = $16$.
Parental phen

Vedclass · Accepted Answer

$F_{2}$ generation,the phenotypic ratio is $9:3:3:1$.

Vedclass · Answer

(D) In a Mendelian dihybrid cross involving two traits,the $F_{2}$ phenotypic ratio is $9:3:3:1$.
Total number of combinations = $16$.
Parental phenotypes (resembling parents $TTRR$ and $ttrr$) are $9$ (dominant-dominant) and $1$ (recessive-recessive),totaling $10$.
Non-parental (recombinant) phenotypes are $3$ and $3$,totaling $6$.
The ratio of parental to non-parental plants is $10:6$,which simplifies to $5:3$.
Option $D$ correctly identifies the standard Mendelian phenotypic ratio for a dihybrid cross.

In the $F_{2}$ generation of a Mendelian dihybrid cross $(TTRR \times ttrr)$,which of the following statements is correct?

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