(A) In the $C_3$-cycle (Calvin cycle),the synthesis of $1$ molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $\text{ATP}$ and $12$ $\text{NADPH}$.To

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(A) In the $C_3$-cycle (Calvin cycle),the synthesis of $1$ molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $\text{ATP}$ and $12$ $\text{NADPH}$.To form $3$ molecules of glucose,we multiply the requirements by $3$.Total $\text{ATP}$ required $= 3 \times 18 = 54$ $\text{ATP}$.Therefore,the correct option is $A$.