In Pb_3O_4, the different oxidation states of | vedclass

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(C) $Pb_3O_4$ is a mixed oxide, which can be represented as $2PbO \cdot PbO_2$. In $PbO$, the oxidation state of $Pb$ is $+2$. In $PbO_2$, the oxidati

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$2$ and $4$

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(C) $Pb_3O_4$ is a mixed oxide, which can be represented as $2PbO \cdot PbO_2$. In $PbO$, the oxidation state of $Pb$ is $+2$. In $PbO_2$, the oxidation state of $Pb$ is $+4$. Calculation for $PbO$: $x + (-2) = 0 \Rightarrow x = +2$. Calculation for $PbO_2$: $x + 2(-2) = 0$ $\Rightarrow x - 4 = 0$ $\Rightarrow x = +4$. Thus, the oxidation states of $Pb$ in $Pb_3O_4$ are $+2$ and $+4$.

In $Pb_3O_4$, the different oxidation states of $Pb$ are:

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