In $CuSO_4$ solution,when an electric current equal to $2.5 \ F$ (faraday) is passed,the number of $gm$ equivalents deposited on the cathode is:

The laws of electrolysis were proposed by

$A$ current $I$ is passed for a time $t$ through a number of voltameters. If $m$ is the mass of a substance deposited on an electrode and $z$ is its electrochemical equivalent,then

According to the first law of Faraday,the weight of a substance discharged at the electrode is:

Assertion $(A)$: The charge on one mole of electrons is one Faraday.
Reason $(R)$: The quantity of current required to deposit one mole of $Mg$ from $Mg^{2+}$ electrolyte solution is two Faradays.
The correct answer is

Silver plating is done on a silver cup by passing a current of $965 \ A$ for $1 \ s$. How many grams of $Ag$ are deposited? $(Ag = 107.87 \ g/mol)$