In the 2^{nd} period,which element has the hi | vedclass

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(A) The ionization energy $(I.E.)$ generally increases across a period from left to right due to an increase in effective nuclear charge.For the $2^{n

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$Ne$

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(A) The ionization energy $(I.E.)$ generally increases across a period from left to right due to an increase in effective nuclear charge.For the $2^{nd}$ period elements $(Li, Be, B, C, N, O, F, Ne)$,the $1^{st}$ $I.E.$ is highest for $Ne$ (noble gas).The $2^{nd}$ $I.E.$ corresponds to the energy required to remove an electron from a unipositive ion $(M^+)$.For $Ne$,the $1^{st}$ $I.E.$ is very high,and the $2^{nd}$ $I.E.$ is even higher because the electron is being removed from a stable octet configuration.Comparing the sum of $1^{st}$ and $2^{nd}$ $I.E.$,$Ne$ has the highest value because both its $1^{st}$ and $2^{nd}$ ionization energies are significantly higher than those of other elements in the same period.

In the $2^{nd}$ period,which element has the highest value of the sum of the $1^{st}$ and $2^{nd}$ ionization energy $(I.E.)$?

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