In a 100, m race,Kamal defeats Bimal by 5 sec | vedclass

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(C) First,convert Kamal's speed from $km/h$ to $m/s$:$18\, km/h = 18 	imes \frac{5}{18} = 5\, m/s$.Time taken by Kamal to complete the $100\, m$ race

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$14.4$

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(C) First,convert Kamal's speed from $km/h$ to $m/s$:$18\, km/h = 18 	imes \frac{5}{18} = 5\, m/s$.Time taken by Kamal to complete the $100\, m$ race:$T_K = \frac{	ext{Distance}}{	ext{Speed}} = \frac{100}{5} = 20\, s$.Since Kamal defeats Bimal by $5$ seconds,Bimal takes $5$ seconds more than Kamal:$T_B = 20 + 5 = 25\, s$.Now,calculate Bimal's speed in $m/s$:$V_B = \frac{100}{25} = 4\, m/s$.Finally,convert Bimal's speed back to $km/h$:$V_B = 4 	imes \frac{18}{5} = 14.4\, km/h$.

In a $100\, m$ race,Kamal defeats Bimal by $5$ seconds. If the speed of Kamal is $18\, km/h$,then the speed of Bimal is .......... $km/h$.

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