In a p-n junction diode not connected to any | vedclass

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(C) When a $p-n$ junction is formed,electrons diffuse from the $n$-region to the $p$-region,and holes diffuse from the $p$-region to the $n$-region. T

Vedclass · Accepted Answer

there is an electric field at the junction directed from the $n$-type side to $p$-type side

Vedclass · Answer

(C) When a $p-n$ junction is formed,electrons diffuse from the $n$-region to the $p$-region,and holes diffuse from the $p$-region to the $n$-region. This leaves behind immobile ionized donors in the $n$-region (positive charge) and immobile ionized acceptors in the $p$-region (negative charge).This creates a depletion region at the junction with a built-in potential difference. The $n$-side becomes positive relative to the $p$-side.Since the electric field lines are directed from positive potential to negative potential,the electric field at the junction is directed from the $n$-type side to the $p$-type side.

In a $p-n$ junction diode not connected to any circuit:

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