In a Delta ABC, if a = 2x, b = 2y and angle C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The area of a triangle is given by the formula $\Delta = \frac{1}{2}ab \sin C.$Given $a = 2x,$ $b = 2y,$ and $\angle C = 120^\circ.$Substituting t

Vedclass · Accepted Answer

$xy\sqrt{3}$

Vedclass · Answer

(B) The area of a triangle is given by the formula $\Delta = \frac{1}{2}ab \sin C.$Given $a = 2x,$ $b = 2y,$ and $\angle C = 120^\circ.$Substituting these values into the formula:$\Delta = \frac{1}{2} 	imes (2x) 	imes (2y) 	imes \sin(120^\circ)$Since $\sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2},$$\Delta = \frac{1}{2} 	imes 4xy 	imes \frac{\sqrt{3}}{2}$$\Delta = 2xy 	imes \frac{\sqrt{3}}{2} = xy\sqrt{3}.$

In a $\Delta ABC,$ if $a = 2x,$ $b = 2y$ and $\angle C = 120^\circ,$ then the area of the triangle is

Similar Questions

If $4$ times the area of a $\triangle ABC$ is $c^2-(a-b)^2$,then $\sin C$ is equal to:

What is the greatest angle of the triangle whose sides are $x^2+x+1, 2x+1, x^2-1$ (in $^{\circ}$)?

$\frac{a\cos A + b\cos B + c\cos C}{a + b + c} = $

In a $\triangle ABC$, $2ac \sin \left(\frac{A-B+C}{2}\right)$ is equal to

In a $\Delta ABC$,if $C = 90^{\circ}$,then $\frac{a^{2} + b^{2}}{a^{2} - b^{2}} \sin(A - B)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module