In a $\triangle ABC$,$2A + C = 300^{\circ}$. If the circumradius $R$ of the $\triangle ABC$ is eight times its inradius $r$,then $\sin \frac{C}{2} = $

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{3}{4+\sqrt{3}}$
  • D
    $\frac{1}{\sqrt{2}+1}$

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