Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
EasyIn a $\triangle ABC$,if $a=2, b=3$ and $\sin A=\frac{2}{3}$,then $\angle B=$
- A$\frac{\pi}{2}$
- B$\frac{\pi}{6}$
- C$\frac{\pi}{3}$
- D$\frac{\pi}{4}$
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MediumAIEEE 2005
View SolutionThe area (in square units) of $\triangle ABC$ if $\angle A=75^{\circ}, \angle B=45^{\circ}$ and $a=2(\sqrt{3}+1)$ is
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