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(D) The output of an $	ext{AND}$ gate is $Y = A \cdot B$.$A$ $	ext{NAND}$ gate is an $	ext{AND}$ gate followed by a $	ext{NOT}$ gate. Therefore, t

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$A=1, B=1; Y=0$

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(D) The output of an $	ext{AND}$ gate is $Y = A \cdot B$.$A$ $	ext{NAND}$ gate is an $	ext{AND}$ gate followed by a $	ext{NOT}$ gate. Therefore, the output of a $	ext{NAND}$ gate is $Y = \overline{A \cdot B}$.According to De Morgan's theorem, $Y = \overline{A} + \overline{B}$.The truth table for the $	ext{NAND}$ gate is as follows:$A$$B$$Y$$0$$0$$1$$0$$1$$1$$1$$0$$1$$1$$1$$0$Comparing this with the given options, when $A=1$ and $B=1$, the output $Y=0$.

In a $\text{NAND}$ gate, $A$ and $B$ are inputs and $Y$ is the output, then the correct option is

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