In a DNA molecule, the percentage of cytosine | vedclass

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(C) According to Chargaff's rule, the amount of adenine $(A)$ is equal to the amount of thymine $(T)$, and the amount of cytosine $(C)$ is equal to th

Vedclass · Accepted Answer

$22$

Vedclass · Answer

(C) According to Chargaff's rule, the amount of adenine $(A)$ is equal to the amount of thymine $(T)$, and the amount of cytosine $(C)$ is equal to the amount of guanine $(G)$.Given: $C = 28\%$.Since $C = G$, then $G = 28\%$.The total percentage of all bases is $A + T + C + G = 100\%$.Since $A = T$, we can write $2A + 2C = 100\%$.Substituting the value of $C$: $2A + 2(28\%) = 100\%$.$2A + 56\% = 100\%$.$2A = 100\% - 56\% = 44\%$.$A = 22\%$.Therefore, the percentage of adenine is $22\%$.

In a $DNA$ molecule, the percentage of cytosine is $28\%$. Calculate the percentage of adenine. (in $\%$)

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