In an AC circuit containing only a capacitor, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a purely capacitive $AC$ circuit,the voltage across the capacitor is given by $V = V_m \sin(\omega t)$.The current in the circuit is given by $

Vedclass · Accepted Answer

Leads the potential

Vedclass · Answer

(A) In a purely capacitive $AC$ circuit,the voltage across the capacitor is given by $V = V_m \sin(\omega t)$.The current in the circuit is given by $I = C \frac{dV}{dt} = C \frac{d}{dt}(V_m \sin(\omega t)) = \omega C V_m \cos(\omega t)$.This can be written as $I = I_m \sin(\omega t + \frac{\pi}{2})$,where $I_m = \omega C V_m$.Comparing the phases,the current leads the potential difference by a phase angle of $\frac{\pi}{2}$ radians (or $90^{\circ}$).Therefore,the current is forward relative to the potential.

In an $AC$ circuit containing only a capacitor,how does the current relate to the potential difference?

Similar Questions

$A$ choke coil is used to control:

What is a resistive circuit? Write the formula for the power consumed in it.

The inductive reactance of a coil is $R \ \Omega$. If the inductance of the coil is tripled and the frequency of the $A.C.$ supply is also tripled,then the new inductive reactance will be:

An alternating $e.m.f.$ of angular frequency $\omega$ is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency

$A$ coil has an inductance of $2 \ H$. The ratio of its reactance,when it is connected first to an $AC$ source and then to a $DC$ source,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module