In a PN- junction diode not connected to any | vedclass

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(C) When a $PN-$ junction is formed,electrons diffuse from the $N-$ region to the $P-$ region,and holes diffuse from the $P-$ region to the $N-$ regio

Vedclass · Accepted Answer

There is an electric field at the junction directed from the $N-$ type side to the $P-$ type side.

Vedclass · Answer

(C) When a $PN-$ junction is formed,electrons diffuse from the $N-$ region to the $P-$ region,and holes diffuse from the $P-$ region to the $N-$ region.This diffusion leaves behind ionized donors in the $N-$ region (positive charge) and ionized acceptors in the $P-$ region (negative charge) near the junction,creating a depletion layer.Due to this charge distribution,a potential barrier is established such that the $N-$ side is at a higher potential than the $P-$ side.Since the electric field $E$ is directed from higher potential to lower potential,the electric field at the junction is directed from the $N-$ type side to the $P-$ type side.

In a $PN-$ junction diode not connected to any circuit:

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