In a $PNP$ transistor,the base is the $N$-region. Its width relative to the $P$-region is

$A$ common emitter amplifier circuit,built using an $npn$ transistor,is shown in the figure. Its $dc$ current gain is $250$,$R_C = 1\,k\Omega$ and $V_{CC} = 10\,V$. What is the minimum base current for $V_{CE}$ to reach saturation? (in $\mu A$)

Consider an $NPN$ transistor amplifier in common-emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1\, mA$,what will be the change in emitter current in $mA$?

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.

In the following common emitter circuit,$\beta=100$ and $V_{CE}=7 \text{ V}$. If $V_{BE}$ is negligible,then the base current is (in $\text{ mA}$)

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is: