In a basic aqueous solution,if the concentrat | vedclass

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(B) The $pOH$ of a solution is defined by the formula: $pOH = -\log_{10}[OH^-]$.Since the $pOH$ is inversely proportional to the logarithm of the hydr

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It increases.

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(B) The $pOH$ of a solution is defined by the formula: $pOH = -\log_{10}[OH^-]$.Since the $pOH$ is inversely proportional to the logarithm of the hydroxide ion concentration,as the concentration of $[OH^-]$ decreases,the value of $\log_{10}[OH^-]$ becomes more negative.Consequently,the negative sign in the formula makes the $pOH$ value increase.Therefore,if the concentration of $[OH^-]$ decreases,the $pOH$ increases.

In a basic aqueous solution,if the concentration of $[OH^-]$ decreases,what happens to the $pOH$?

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