In a capillary tube experiment, a vertical $30 \text{ cm}$ long capillary tube is dipped in water. Water rises up to a height of $10 \text{ cm}$ due to capillarity. If this experiment is conducted in a freely falling elevator, then the length of the water column becomes

The following observations were taken for determining surface tension $T$ of water by the capillary method:
Diameter of capillary,$D = 1.25 \times 10^{-2} \; m$
Rise of water,$h = 1.45 \times 10^{-2} \; m$
Using $g = 9.80 \; m/s^2$ and the simplified relation $T = \frac{rhg}{2} \times 10^3 \; N/m$,the possible error in surface tension is ........... $\%$. (Assume the least count of the measuring instrument is $0.01 \times 10^{-2} \; m$)

The height up to which water will rise in a capillary tube will be

$A$ capillary tube $(A)$ is dipped in water. Another identical tube $(B)$ is dipped in a soap-water solution. Which of the following shows the relative nature of the liquid columns in the two tubes?

When a capillary is dipped in water,water rises $0.015 \ m$ in it. If the surface tension of water is $75 \times 10^{-3} \ N/m$,the radius of the capillary is ....... $mm$.

$A$ capillary tube of radius '$r$' is immersed in water and water rises to a height of '$h$'. The mass of water in the capillary tube is $5 \times 10^{-3} \ kg$. The same capillary tube is now immersed in a liquid whose surface tension is $\sqrt{2}$ times the surface tension of water. The angle of contact between the capillary tube and this liquid is $45^{\circ}$. The mass of liquid which rises into the capillary tube now is (in $kg$):