In a certain code DAYLONG is written as ZBEKH | vedclass

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(D) Analyze the pattern in $DAYLONG$ to $ZBEKHOP$:$D + 1 = E$,$A + 1 = B$,$Y + 1 = Z$ (reversed: $ZBE$)$L + 1 = M$,$O + 1 = P$,$N + 1 = O$,$G + 1 = H$

Vedclass · Accepted Answer

$SPDCJBM$

Vedclass · Answer

(D) Analyze the pattern in $DAYLONG$ to $ZBEKHOP$:$D + 1 = E$,$A + 1 = B$,$Y + 1 = Z$ (reversed: $ZBE$)$L + 1 = M$,$O + 1 = P$,$N + 1 = O$,$G + 1 = H$ (reversed: $HOP$)Wait,let's re-examine: $D(4) \rightarrow Z(26)$,$A(1) \rightarrow B(2)$,$Y(25) \rightarrow E(5)$,$L(12) \rightarrow K(11)$,$O(15) \rightarrow H(8)$,$N(14) \rightarrow O(15)$,$G(7) \rightarrow P(16)$.Actually,the pattern is: Reverse the word $DAYLONG$ to $GNOLYAD$,then add $1$ to each letter: $G+1=H, N+1=O, O+1=P, L+1=M, Y+1=Z, A+1=B, D+1=E$. This gives $HOPMZBE$. This does not match.Let's try: $D+1=E, A+1=B, Y+1=Z$ (first $3$ letters reversed) and $L+1=M, O+1=P, N+1=O, G+1=H$ (last $4$ letters reversed).$DAY \rightarrow Y+1=Z, A+1=B, D+1=E \rightarrow ZBE$.$LONG \rightarrow G+1=H, N+1=O, O+1=P, L+1=M \rightarrow HOPM$.Combining gives $ZBEHOPM$. The question states $ZBEKHOP$. Let's re-check: $D-1=C, A+1=B, Y+1=Z$. No.Correct logic: $D+1=E, A+1=B, Y+1=Z$ (reversed: $ZBE$). $L-1=K, O+1=P, N+1=O, G+1=H$ (reversed: $HOPK$).Applying to $CORDIAL$: $COR \rightarrow R+1=S, O+1=P, C+1=D \rightarrow SPD$. $DIAL \rightarrow L+1=M, A+1=B, I+1=J, D+1=C$ (reversed: $CJBM$).Result: $SPDCJBM$.

In a certain code $DAYLONG$ is written as $ZBEKHOP$. How is $CORDIAL$ written in that code?

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