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(D) Let the total number of seats be $x$. Ticket price per seat $= ₹ 200$. On the first day,$60 \%$ of seats were filled,so the number of spectators $

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$20$

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(D) Let the total number of seats be $x$. Ticket price per seat $= ₹ 200$. On the first day,$60 \%$ of seats were filled,so the number of spectators $= 0.6x$. Total revenue on the first day $= 0.6x 	imes 200 = 120x$. On the second day,the price is reduced by $20 \%$,so the new price $= 200 - (0.20 	imes 200) = ₹ 160$. The number of spectators increased by $50 \%$,so the new number of spectators $= 0.6x + (0.50 	imes 0.6x) = 0.6x + 0.3x = 0.9x$. Total revenue on the second day $= 0.9x 	imes 160 = 144x$. Percentage increase in revenue $= \frac{144x - 120x}{120x} 	imes 100 = \frac{24x}{120x} 	imes 100 = \frac{1}{5} 	imes 100 = 20 \%$.

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