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(C) The area of a sector of a circle with radius $r$ and central angle $	heta$ is given by the formula: $A = \frac{	heta}{360^{\circ}} 	imes \pi r^

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$1: 6$

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(C) The area of a sector of a circle with radius $r$ and central angle $	heta$ is given by the formula: $A = \frac{	heta}{360^{\circ}} 	imes \pi r^2$.Let the two sectors have angles $	heta_1 = 15^{\circ}$ and $	heta_2 = 90^{\circ}$.The ratio of the areas of the two sectors is:$\frac{A_1}{A_2} = \frac{\frac{	heta_1}{360^{\circ}} 	imes \pi r^2}{\frac{	heta_2}{360^{\circ}} 	imes \pi r^2} = \frac{	heta_1}{	heta_2}$.Substituting the given values:$\frac{A_1}{A_2} = \frac{15^{\circ}}{90^{\circ}} = \frac{1}{6}$.Thus,the ratio of the areas of the sectors is $1: 6$.

In a circle with radius $20 \,cm$,the measures of the angle subtended at the centre for two distinct sectors are $15^{\circ}$ and $90^{\circ}$. Then,the ratio of the areas of those sectors is $\ldots \ldots \ldots$.

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