In a circle with radius 8.4 , cm,two radii ar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The radius of the circle is $r = 8.4 \, cm$.Since the two radii are perpendicular to each other,the central angle of the minor sector is $	heta =

Vedclass · Accepted Answer

$55.44$

Vedclass · Answer

(B) The radius of the circle is $r = 8.4 \, cm$.Since the two radii are perpendicular to each other,the central angle of the minor sector is $	heta = 90^\circ$.The formula for the area of a sector is $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$.Substituting the values: $	ext{Area} = \frac{90^\circ}{360^\circ} 	imes \frac{22}{7} 	imes (8.4)^2$.$	ext{Area} = \frac{1}{4} 	imes \frac{22}{7} 	imes 8.4 	imes 8.4$.$	ext{Area} = \frac{1}{4} 	imes 22 	imes 1.2 	imes 8.4$.$	ext{Area} = 5.5 	imes 1.2 	imes 8.4 = 55.44 \, cm^2$.

Part $I$	Part $II$
$1. \overline{OA} \cup \overline{OB} \cup \widehat{APB}$	$a. \text{Major sector}$
$2. \overline{AB} \cup \widehat{AQB}$	$b. \text{Minor segment}$
$3. \overline{AB} \cup \widehat{APB}$	$c. \text{Minor sector}$
$4. \overline{OA} \cup \overline{OB} \cup \widehat{AQB}$	$d. \text{Major segment}$

In a circle with radius $8.4 \, cm$,two radii are perpendicular to each other. The area of the minor sector formed by these radii is $\ldots \ldots \ldots \, cm^2$.

Similar Questions

The ratio of radii of two circles is $2:3$ and the ratio of the angles at the centre of two minor sectors of those circles is $5:2$. Then,the ratio of the areas of those sectors is:

Find the area of the sector of a circle of radius $5\, cm$,if the corresponding arc length is $3.5\, cm$. (in $cm^2$)

If the radius of a circle is doubled,its area becomes $\ldots \ldots \ldots$ times the area of the original circle.

In $\odot(O, 7),$ the length of $\widehat{ABC}$ is $14.$ Then,$\ldots \ldots$ holds good.

Vedclass Test Series

Exam Paper Generator

Online Exam Module