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(C) The voltage gain $(A_v)$ of a common emitter transistor amplifier is given by the formula:$A_v = \beta 	imes \frac{R_L}{R_i}$Where:$\beta$ ($AC$

Vedclass · Accepted Answer

$780$

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(C) The voltage gain $(A_v)$ of a common emitter transistor amplifier is given by the formula:$A_v = \beta 	imes \frac{R_L}{R_i}$Where:$\beta$ ($AC$ current gain) = $65$$R_L$ (Load resistance) = $5400 	ext{ }\Omega$$R_i$ (Input resistance) = $450 	ext{ }\Omega$Substituting the values into the formula:$A_v = 65 	imes \frac{5400}{450}$$A_v = 65 	imes 12$$A_v = 780$Therefore, the voltage gain is $780$.

In a common emitter transistor amplifier, $AC$ current gain is $65$, the load resistance is $5400 \text{ }\Omega$ and input resistance of the transistor is $450 \text{ }\Omega$. The voltage gain is

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