In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of

Consider the circuit arrangement shown in figure $(1)$ for studying input and output characteristics of an $n-p-n$ transistor in $CE$ configuration. Select the values of $R_B$ and $R_C$ for a transistor whose $V_{BE} = 0.7 \, V$, so that the transistor is operating at point $Q$ as shown in the characteristics shown in figure $(2)$. Given that the input impedance of the transistor is very small and $V_{CC} = V_{BB} = 16 \, V$, also find the voltage gain and power gain of the circuit making appropriate assumptions.

$A$ common-emitter amplifier is designed with a $n-p-n$ transistor $(\alpha = 0.99)$. The input impedance is $1\, k\Omega$ and load is $10\, k\Omega$. The voltage gain will be

In a $NPN$ transistor,$10^8$ electrons enter the emitter in $10^{-8} \ s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively:

$A$ transistor having $\alpha=0.8$ is connected in a common-emitter configuration. When the base current changes by $6 \text{ mA}$, the change in collector current is: (in $\text{ mA}$)

In a common-emitter transistor amplifier,$\beta = 50$ and the input resistance is $1 \ k\Omega$. If the peak value of the $AC$ input voltage is $0.01 \ V$,then the peak value of the $AC$ collector current will be .......