In a common emitter transistor circuit,the ba | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Applying Kirchhoff's voltage law to the base-emitter loop:$V_{CC} - I_B R_B = V_{BE}$Given:$V_{CC} = 10 \, V$$I_B = 40 \,\mu A = 40 	imes 10^{-6}

Vedclass · Accepted Answer

$0.2$

Vedclass · Answer

(B) Applying Kirchhoff's voltage law to the base-emitter loop:$V_{CC} - I_B R_B = V_{BE}$Given:$V_{CC} = 10 \, V$$I_B = 40 \,\mu A = 40 	imes 10^{-6} \, A$$R_B = 245 \, k\Omega = 245 	imes 10^3 \, \Omega$Substituting the values:$V_{BE} = 10 - (40 	imes 10^{-6} 	imes 245 	imes 10^3)$$V_{BE} = 10 - (40 	imes 245 	imes 10^{-3})$$V_{BE} = 10 - (9800 	imes 10^{-3})$$V_{BE} = 10 - 9.8$$V_{BE} = 0.2 \, V$Thus,the correct option is $B$.

In a common emitter transistor circuit,the base current is $40 \,\mu A$. Find the value of $V_{BE}$ in volts.

Similar Questions

In the circuit shown,the power factor of the circuit is $1$ and the power factor of the box is $\frac{3}{5}$. Find the reading of the ammeter in $A$.

Which of the following is the correct order of lattice energy for the given ionic compounds?

If $x y \neq 0, x+y \neq 0$ and $x^m y^n=(x+y)^{m+n}$, where $m, n \notin N$, then $\frac{d y}{d x}$ is equal to

Which of the following statements is correct for any thermodynamic system?

If the system of linear equations $x + 2ay + az = 0$,$x + 3by + bz = 0$,and $x + 4cy + cz = 0$ has a non-zero solution,then $a, b, c$:

Vedclass Test Series

Exam Paper Generator

Online Exam Module