In a competitive examination,the average mark | vedclass

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(C) Let the total number of candidates be $x$.Initially,the total marks obtained by all candidates $= 45x$.When the marks of $90$ candidates were chan

Vedclass · Accepted Answer

$540$

Vedclass · Answer

(C) Let the total number of candidates be $x$.Initially,the total marks obtained by all candidates $= 45x$.When the marks of $90$ candidates were changed from $80$ to $50$,the reduction in marks for each candidate is $80 - 50 = 30$.Total reduction in marks for $90$ candidates $= 90 	imes 30 = 2700$.The new total marks $= 45x - 2700$.The new average is given as $40$.Therefore,$\frac{45x - 2700}{x} = 40$.Multiplying both sides by $x$,we get $45x - 2700 = 40x$.Rearranging the terms,$45x - 40x = 2700$.$5x = 2700$.$x = \frac{2700}{5} = 540$.Thus,the total number of candidates is $540$.

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