In a competitive examination in state A,6% of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $x$ be the total number of candidates who appeared from each state $A$ and $B$.Number of candidates selected from state $A = \frac{6}{100}x =

Vedclass · Accepted Answer

$8000$

Vedclass · Answer

(B) Let $x$ be the total number of candidates who appeared from each state $A$ and $B$.Number of candidates selected from state $A = \frac{6}{100}x = 0.06x$.Number of candidates selected from state $B = \frac{7}{100}x = 0.07x$.According to the problem,the number of candidates selected from state $B$ is $80$ more than those from state $A$:$0.07x - 0.06x = 80$.$0.01x = 80$.$x = \frac{80}{0.01} = 8000$.Therefore,the number of candidates who appeared from each state is $8000$.

Similar Questions

$15 \%$ of $578 + 22.5 \%$ of $644 = ?$

$\frac{3}{4}$ of $\frac{2}{3}$ of $\frac{1}{5}$ of a number is $249.6$. What is $50\%$ of that number?

What percentage is equivalent to $5 \frac{1}{4}$?

If the price of apple increases from $Rs$ $80$ per $kg$ to $Rs$ $100$ per $kg$,by what percent should a person decrease the consumption of apple so that his expenditure remains the same (in $\%$)?

During one year,the population of a town was increased by $5 \%$ and during the next year,the population decreased by $5 \%$. If the total population is $9975$ at the end of the second year,then what was the population size in the beginning of the first year?

Vedclass Test Series

Exam Paper Generator

Online Exam Module