In a complexometric titration of a metal ion | vedclass

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Question

(A) Initially,the ligand is consumed by the metal ion to form the complex $(C)$. Since neither the metal ion $(M)$ nor the complex $(C)$ absorbs light

Vedclass · Accepted Answer

Vedclass · Answer

(A) Initially,the ligand is consumed by the metal ion to form the complex $(C)$. Since neither the metal ion $(M)$ nor the complex $(C)$ absorbs light,the absorbance $(A)$ remains near zero or constant during this phase.After the equivalence point is reached,all metal ions have been converted into the complex. Any further addition of the ligand $(L)$ increases its concentration in the solution.Since the ligand $(L)$ absorbs light,the absorbance $(A)$ starts to increase linearly with the volume of the added ligand $(V)$.Therefore,the plot shows a horizontal line followed by an upward slope,which corresponds to the graph in option $A$.

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