In a compound microscope,the focal length of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the objective lens,using the lens formula $\frac{1}{v_o} - \frac{1}{u_o} = \frac{1}{f_o}$:Given $u_o = -1.25 \ cm$ and $f_o = 1.2 \ cm$,we hav

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(A) For the objective lens,using the lens formula $\frac{1}{v_o} - \frac{1}{u_o} = \frac{1}{f_o}$:Given $u_o = -1.25 \ cm$ and $f_o = 1.2 \ cm$,we have $\frac{1}{v_o} = \frac{1}{1.2} - \frac{1}{1.25} = \frac{1.25 - 1.2}{1.5} = \frac{0.05}{1.5} = \frac{1}{30}$.So,$v_o = 30 \ cm$.The magnification of the objective lens is $m_o = \frac{v_o}{u_o} = \frac{30}{-1.25} = -24$.For the eyepiece,when the final image is at infinity,the magnifying power is $m_e = \frac{D}{f_e}$,where $D = 25 \ cm$ is the least distance of distinct vision.$m_e = \frac{25}{3.0} = \frac{25}{3} \approx 8.33$.The total magnifying power $M = m_o 	imes m_e = -24 	imes \frac{25}{3} = -8 	imes 25 = -200$.The magnitude of the magnifying power is $|M| = 200$.

Similar Questions

Let $p = (x + 4y)\,a + (2x + y + 1)\,b$ and $q = (y - 2x + 2)\,a + (2x - 3y - 1)\,b,$ where $a$ and $b$ are non-collinear vectors. If $3p = 2q,$ then the values of $x$ and $y$ are:

Let $A = \begin{bmatrix} 1 & -1 & 1 \\ 2 & 1 & -3 \\ 1 & 1 & 1 \end{bmatrix}$ and $10B = \begin{bmatrix} 4 & 2 & 2 \\ -5 & 0 & \alpha \\ 1 & -2 & 3 \end{bmatrix}$. If $B$ is the inverse of matrix $A$,then $\alpha$ is:

What type of relationship is observed between insect-pollinated flowers and their pollinating insects?

In an $LCR$ circuit,the capacitance is changed from $C$ to $2C$. For the resonant frequency to remain unchanged,the inductance should be changed from $L$ to:

The temperature-entropy $(T-S)$ diagram of a reversible engine cycle is given in the figure. Its efficiency is

Vedclass Test Series

Exam Paper Generator

Online Exam Module