In a compound microscope,the objective lens and eyepiece have focal lengths of $0.95 \ cm$ and $5 \ cm$ respectively,and are kept at a distance of $20 \ cm$. The final image is formed at a distance of $25 \ cm$ from the eyepiece. Calculate the magnifying power.

  • A
    $94$
  • B
    $84$
  • C
    $75$
  • D
    $88$

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Similar Questions

$A$ person with a normal near point $(25 \;cm)$ using a compound microscope with an objective of focal length $8.0 \;mm$ and an eyepiece of focal length $2.5 \;cm$ can bring an object placed at $9.0 \;mm$ from the objective into sharp focus. What is the separation between the two lenses? Calculate the magnifying power of the microscope.

The maximum magnification that can be obtained with a convex lens of focal length $2.5\, cm$ is (the least distance of distinct vision is $25\, cm$).

An angular magnification (magnifying power) of $30X$ is desired using an objective of focal length $1.25 \, cm$ and an eyepiece of focal length $5 \, cm$. How will you set up the compound microscope?

Write the equation of magnification for a simple microscope when the image is formed at the near point.

Mention the maximum magnification of a simple microscope.

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