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(C) The height $h$ of the bridge is given by the equation of motion: $h = \frac{1}{2}gt^2$.Given $g = 9.8\;m/s^2$ and $t = 2\;s$,the height is $h = \f

Vedclass · Accepted Answer

$1.96$

Vedclass · Answer

(C) The height $h$ of the bridge is given by the equation of motion: $h = \frac{1}{2}gt^2$.Given $g = 9.8\;m/s^2$ and $t = 2\;s$,the height is $h = \frac{1}{2} 	imes 9.8 	imes (2)^2 = 19.6\;m$.To find the error in height $\Delta h$,we differentiate the equation $h = \frac{1}{2}gt^2$ with respect to $t$:$dh = gt \cdot dt$.Substituting the given values,where $dt = \Delta t = 0.1\;s$:$\Delta h = 9.8 	imes 2 	imes 0.1 = 1.96\;m$.Thus,the error in the estimation of the height is $1.96\;m$.

In an experiment to measure the height of a bridge by dropping a stone into water underneath,if the error in the measurement of time is $0.1\;s$ at the end of $2\;s$,then the error in the estimation of the height of the bridge will be (in $;m$)

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