In a family,a couple has a son and a daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is $9$ years younger than her husband and the brother is $7$ years older than his sister. What is the age of the mother? (in years)

One $year$ ago the ratio between Samir and Ashok's age was $4: 3$. One year hence the ratio of their ages will be $5: 4$. What is the sum of their present ages in $years$?

The sum of the ages of $4$ members of a family,$5$ $years$ ago,was $94$ $years$. Today,when the daughter has been married off and replaced by a daughter-in-law,the sum of their ages is $92$ $years$. Assuming that there has been no other change in the family structure and all the people are alive,what is the difference between the age of the daughter and that of the daughter-in-law? (in $years$)

Eighteen $years$ ago,a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is

$7$ years ago,the ages (in years) of $A$ and $B$ were in the ratio $4:5$; and $7$ years hence they will be in the ratio $5:6$. The present age of $B$ is (in years):

The ratio between the ages of a father and a son at present is $5:2$. $4$ years hence,the ratio between the ages of the son and his mother will be $1:2$. What is the ratio between the present ages of the father and the mother?