In a first order reaction,the concentration o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a first order reaction,the half-life period $(T_{1/2})$ is the time required for the concentration to become half of its initial value.Given t

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(C) For a first order reaction,the half-life period $(T_{1/2})$ is the time required for the concentration to become half of its initial value.Given that the concentration decreases from $0.8 \ M$ to $0.4 \ M$ in $15 \ min$,this represents one half-life,so $T_{1/2} = 15 \ min$.To find the time taken for the concentration to change from $0.1 \ M$ to $0.025 \ M$,we observe the number of half-lives:$0.1 \ M$ $\xrightarrow{T_{1/2}} 0.05 \ M$ $\xrightarrow{T_{1/2}} 0.025 \ M$.This process involves $2$ half-lives.Therefore,the total time taken $= 2 	imes T_{1/2} = 2 	imes 15 \ min = 30 \ min$.

$S$.No.	Time	Total pressure in Pascal
$1$.	At the end of $10 \ min$	$300$
$2$.	After completion	$200$

In a first order reaction,the concentration of the reactant decreases from $0.8 \ M$ to $0.4 \ M$ in $15 \ min$. The time taken for the concentration to change from $0.1 \ M$ to $0.025 \ M$ is .......... $min$.

Similar Questions

The following data is obtained during the first order thermal decomposition of $2A_{(g)} \longrightarrow B_{(g)} + C_{(s)}$ at constant volume and temperature. The rate constant in $min^{-1}$ is:
$S$.No. Time Total pressure in Pascal
$1$. At the end of $10 \ min$ $300$
$2$. After completion $200$

The integrated rate law equation for a first-order gas-phase reaction $A(g) \rightarrow B(g) + C(g)$ is given by (where $P_i$ is the initial pressure and $P_t$ is the total pressure at time $t$):

The rate constant of a first order reaction is $1.15 \times 10^{-3} \ s^{-1}$. How long will $5 \ g$ of reactant take to reduce to $3 \ g$ (in $s$)?

In the reaction $2N_2O_5 \to 4NO_2 + O_2$,the initial pressure is $500 \ atm$ and the rate constant $K$ is $3.38 \times 10^{-5} \ s^{-1}$. After $10 \ minutes$,the final pressure of $N_2O_5$ is ........ $atm$.

For a first order gas phase reaction:
$A_{(g)} \rightarrow 2 B_{(g)} + C_{(g)}$
Let $P_0$ be the initial pressure of $A$ and $P_t$ be the total pressure at time $t$. The integrated rate equation is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module