In a fission reaction {}_{92}^{236}U to {}^{1 | vedclass

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(C) The energy released in a nuclear reaction is given by the difference in total binding energy of the products and the reactants.Total binding energ

Vedclass · Accepted Answer

$200\, MeV$

Vedclass · Answer

(C) The energy released in a nuclear reaction is given by the difference in total binding energy of the products and the reactants.Total binding energy of reactants = $236 	imes 7.6\, MeV = 1793.6\, MeV$.Total binding energy of products = $(117 + 117) 	imes 8.5\, MeV = 234 	imes 8.5\, MeV = 1989\, MeV$.Energy liberated = $	ext{Total BE of products} - 	ext{Total BE of reactants} = 1989\, MeV - 1793.6\, MeV = 195.4\, MeV$.This is approximately $200\, MeV$.

In a fission reaction ${}_{92}^{236}U \to {}^{117}X + {}^{117}Y + n + n,$ the binding energy per nucleon of $X$ and $Y$ is $8.5\, MeV$ whereas that of ${}^{236}U$ is $7.6\, MeV$. The total energy liberated will be about:

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