In a fixed time,a boy swims double the distan | vedclass

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(B) Let the rate of swimming in still water be $x 	ext{ km/h}$.The speed of the boy downstream (along the current) is $(x + 3) 	ext{ km/h}$.The spee

Vedclass · Accepted Answer

$9$

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(B) Let the rate of swimming in still water be $x 	ext{ km/h}$.The speed of the boy downstream (along the current) is $(x + 3) 	ext{ km/h}$.The speed of the boy upstream (against the current) is $(x - 3) 	ext{ km/h}$.Since the time $t$ is fixed,and distance = speed $	imes$ time,the problem states that the distance covered downstream is double the distance covered upstream:$(x + 3) 	imes t = 2 	imes (x - 3) 	imes t$Dividing both sides by $t$ (assuming $t 
eq 0$):$x + 3 = 2(x - 3)$$x + 3 = 2x - 6$$x = 9 	ext{ km/h}$.Thus,the rate of swimming in still water is $9 	ext{ km/h}$.

In a fixed time,a boy swims double the distance along the current that he swims against the current. If the speed of the current is $3 \text{ km/h}$,then find the rate of swimming in still water in $\text{km/h}$.

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