In a frequency distribution,the mid value of | vedclass

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(B) The mid value (class mark) of a class is given by the formula: $	ext{Mid value} = \frac{	ext{Lower limit} + 	ext{Upper limit}}{2}$.Let the lowe

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) The mid value (class mark) of a class is given by the formula: $	ext{Mid value} = \frac{	ext{Lower limit} + 	ext{Upper limit}}{2}$.Let the lower limit be $L$ and the upper limit be $U$. The width of the class is $U - L = 6$,which implies $U = L + 6$.Substituting the values into the mid value formula:$10 = \frac{L + (L + 6)}{2}$$10 = \frac{2L + 6}{2}$$10 = L + 3$$L = 10 - 3 = 7$.Therefore,the lower limit of the class is $7$.

Class	$0-5$	$5-10$	$10-20$	$20-30$	$30-50$	$50-70$	$70-100$
Frequency	$6$	$8$	$14$	$16$	$24$	$20$	$30$

Score $(x)$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
Frequency $(f)$	$5$	$9$	$12$	$17$	$14$	$10$	$6$

In a frequency distribution,the mid value of a class is $10$ and the width of the class is $6$. The lower limit of the class is:

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