In a Freundlich adsorption isotherm,if the slope is unity and $k$ is $0.1$,the extent of adsorption at $2 \ atm$ is $(\log 2 = 0.30)$

Which forces are involved in physical adsorption?

The decomposition of phosphine $(PH_3)$ on tungsten at low pressure is a first-order reaction. It is because the

Plot of $\log \left( \frac{x}{m} \right)$ against $\log P$ is a straight line inclined at an angle of $45^o$. When the pressure is $0.5 \ atm$ and Freundlich parameter,$k$ is $10$,the amount of solute adsorbed per gram of adsorbent will be ...... $g$ $(\log 5 = 0.6990)$

The shape of the adsorption isobar for physical adsorption and the adsorption isobar for chemisorption, respectively, are:

Adsorption of a gas on a surface follows the Freundlich adsorption isotherm. The plot of $\log \frac{x}{m}$ versus $\log P$ gives a straight line with a slope equal to $0.5$. Then,(where $\frac{x}{m}$ is the mass of the gas adsorbed per gram of adsorbent):