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(A) In the given circuit,the inputs $A$ and $B$ are passed through $NOT$ gates before being fed into an $OR$ gate.Let $A$ and $B$ be the input signals

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(A) In the given circuit,the inputs $A$ and $B$ are passed through $NOT$ gates before being fed into an $OR$ gate.Let $A$ and $B$ be the input signals where $1$ represents high and $0$ represents low.From the waveform,the sequence for $A$ is $1, 0, 1, 0$ and for $B$ is $1, 1, 0, 0$.After passing through the $NOT$ gates,the inputs to the $OR$ gate become $A' = 0, 1, 0, 1$ and $B' = 0, 0, 1, 1$.The $OR$ gate performs the operation $Y = A' + B'$.Calculating the output sequence:For the first interval: $0 + 0 = 0$For the second interval: $1 + 0 = 1$For the third interval: $0 + 1 = 1$For the fourth interval: $1 + 1 = 1$Thus,the resultant sequence for $Y$ is $0, 1, 1, 1$. This corresponds to option $A$.

In the given circuit as shown,two input waveforms $A$ and $B$ are applied simultaneously. The resultant waveform $Y$ is:

Similar Questions

Choose the correct logic circuit for the given truth table having inputs $A$ and $B$.
Inputs Inputs Outputs
$A$ $B$ $Y$
$0$ $0$ $0$
$0$ $1$ $0$
$1$ $0$ $1$
$1$ $1$ $1$

The symbolic representations of four logic gates are given below. The logic symbols for $OR$,$NOT$,and $NAND$ gates are respectively:

In the given network of $AND$ and $OR$ gates, the output $Q$ can be written as (assuming $n$ is even):

Boolean algebra is essentially based on

The Boolean equation $A + \bar{A} = .......$

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Inputs	Inputs	Outputs
$A$	$B$	$Y$
$0$	$0$	$0$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$