In a group of 1000 people,there are 750 peopl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $H$ be the set of people who speak Hindi and $E$ be the set of people who speak English.Given: $n(H \cup E) = 1000$,$n(H) = 750$,$n(E) = 400$.

Vedclass · Accepted Answer

$600$

Vedclass · Answer

(A) Let $H$ be the set of people who speak Hindi and $E$ be the set of people who speak English.Given: $n(H \cup E) = 1000$,$n(H) = 750$,$n(E) = 400$.Using the formula: $n(H \cup E) = n(H) + n(E) - n(H \cap E)$.Substituting the values: $1000 = 750 + 400 - n(H \cap E)$.$1000 = 1150 - n(H \cap E)$.$n(H \cap E) = 1150 - 1000 = 150$.Number of people who can speak Hindi only is given by $n(H) - n(H \cap E)$.$= 750 - 150 = 600$.

In a group of $1000$ people,there are $750$ people who can speak Hindi and $400$ who can speak English. How many can speak Hindi only?

Similar Questions

Find the cardinal number of the following set ${x: x = 2n, n \in N, 4 \leq x \leq 11}$.

Let $X = \{ 1, 2, 3, 4, 5 \}$ and $Y = \{ 1, 3, 5, 7, 9 \}$. Which of the following is/are relations from $X$ to $Y$?

If $n(U) = 600$,$n(A) = 100$,$n(B) = 200$,and $n(A \cap B) = 50$,then $n(\bar{A} \cap \bar{B})$ is (where $U$ is the universal set and $A$ and $B$ are subsets of $U$).

Let $U = \{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 \}$,$A = \{ 1, 2, 5 \}$,and $B = \{ 6, 7 \}$. Then $A \cap B'$ is:

If $A = \{a, d\}, B = \{b, c, e\}$ and $C = \{b, c, f\},$ then $A \times (B \cap C) =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module