In a hydrogen discharge tube,it is observed t | vedclass

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(A) The electric current $I$ is defined as the rate of flow of net charge through a cross-section.Electrons moving from right to left constitute a cur

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$1\,mA$ towards right

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(A) The electric current $I$ is defined as the rate of flow of net charge through a cross-section.Electrons moving from right to left constitute a current from left to right.Protons moving from left to right constitute a current from left to right.Since both currents are in the same direction,they add up.$I = I_e + I_p = (n_e e) + (n_p e) = (n_e + n_p)e$Given $n_e = 3.13 	imes 10^{15}$ and $n_p = 3.12 	imes 10^{15}$,and $e = 1.6 	imes 10^{-19}\,C$.$I = (3.13 	imes 10^{15} + 3.12 	imes 10^{15}) 	imes 1.6 	imes 10^{-19}\,A$$I = (6.25 	imes 10^{15}) 	imes 1.6 	imes 10^{-19}\,A$$I = 10 	imes 10^{-4}\,A = 10^{-3}\,A = 1\,mA$.Since both components of the current are directed from left to right,the total current is $1\,mA$ towards the right.

In a hydrogen discharge tube,it is observed that through a given cross-section,$3.13 \times 10^{15}$ electrons are moving from right to left and $3.12 \times 10^{15}$ protons are moving from left to right per second. What is the electric current in the discharge tube and what is its direction?

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