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Question

(D) The electric displacement vector $\vec D$ is defined as the product of the permittivity of the medium $\varepsilon$ and the electric field $\vec E

Vedclass · Accepted Answer

$K\varepsilon_0\vec E$

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(D) The electric displacement vector $\vec D$ is defined as the product of the permittivity of the medium $\varepsilon$ and the electric field $\vec E$.$\vec D = \varepsilon \vec E$We know that the permittivity of a medium $\varepsilon$ is related to the permittivity of free space $\varepsilon_0$ and the dielectric constant $K$ by the relation:$\varepsilon = K\varepsilon_0$Substituting this into the expression for $\vec D$:$\vec D = (K\varepsilon_0)\vec E$Therefore,the electric displacement vector is $K\varepsilon_0\vec E$.

In a medium of dielectric constant $K$,the electric field is $\vec E$. If $\varepsilon_0$ is the permittivity of free space,the electric displacement vector is:

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