In a meter bridge experiment, two resistances $X$ and $Y$ in the two gaps give a null point dividing the wire in the ratio $2 : 3$. When each resistance is increased by $30 \text{ } \Omega$, the null point divides the wire in the ratio $5 : 6$. The resistances $X$ and $Y$ are respectively:
- A$20 \text{ } \Omega, 30 \text{ } \Omega$
- B$22 \text{ } \Omega, 33 \text{ } \Omega$
- C$32 \text{ } \Omega, 48 \text{ } \Omega$
- D$40 \text{ } \Omega, 60 \text{ } \Omega$
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Similar Questions
In a meter bridge (Figure), the null point is found at a distance of $33.7 \; cm$ from $A$. If now a resistance of $12 \; \Omega$ is connected in parallel with $S$, the null point occurs at $51.9 \; cm$. Determine the values of $R$ and $S$.
Medium
View SolutionThe resistance per centimeter of a meter bridge wire is $r$. $A$ resistance of $X \ \Omega$ is placed in the left gap and a resistance of $25 \ \Omega$ is placed in the right gap. The balancing length from the left end is $40 \ cm$. Now,the wire is replaced by another wire of $2r$ resistance per centimeter. The new balancing length for the same settings will be at: (in $cm$)
DifficultJEE MAIN 2024
View SolutionIn the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance of $0.1 \, \Omega/cm$. The value of the unknown resistance $X$ and the current drawn from the battery of negligible internal resistance are:
Medium
View Solution$A$ student obtained the following observations in an experiment of a meter bridge to find the unknown resistance of the circuit. The most accurate value of the unknown resistance is ............ $\Omega$.
$S.No.$ $R$ $l$ $100-l$ $S = \left( \frac{100-l}{l} \right)R$ $1$ $20\,\Omega$ $43$ $57$ $26.51\,\Omega$ $2$ $30\,\Omega$ $51$ $49$ $28.82\,\Omega$ $3$ $40\,\Omega$ $59$ $41$ $27.80\,\Omega$ $4$ $60\,\Omega$ $70$ $30$ $25.71\,\Omega$
| $S.No.$ | $R$ | $l$ | $100-l$ | $S = \left( \frac{100-l}{l} \right)R$ |
| $1$ | $20\,\Omega$ | $43$ | $57$ | $26.51\,\Omega$ |
| $2$ | $30\,\Omega$ | $51$ | $49$ | $28.82\,\Omega$ |
| $3$ | $40\,\Omega$ | $59$ | $41$ | $27.80\,\Omega$ |
| $4$ | $60\,\Omega$ | $70$ | $30$ | $25.71\,\Omega$ |
Medium
View SolutionIn a meter bridge,the null point is found at a distance of $25\, cm$ from $A$. If now a resistance of $10\,\Omega$ is connected in parallel with $S$,the null point occurs at the midpoint of $AB$. The value of $R$ is ................. $\Omega$. (in $.67$)
Medium
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