In a mixture of 60 L,the ratio of milk and w | vedclass

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(B) Total quantity of the mixture = $60 \ L$.The ratio of milk to water is $2:1$.Sum of ratio parts = $2 + 1 = 3$.Quantity of milk = $(2/3) 	imes 60

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(B) Total quantity of the mixture = $60 \ L$.The ratio of milk to water is $2:1$.Sum of ratio parts = $2 + 1 = 3$.Quantity of milk = $(2/3) 	imes 60 = 40 \ L$.Quantity of water = $(1/3) 	imes 60 = 20 \ L$.Let the quantity of water to be added be $x \ L$.After adding water,the new quantity of water = $(20 + x) \ L$.The new ratio of milk to water is $1:3$.So,$40 / (20 + x) = 1 / 3$.$40 	imes 3 = 20 + x$.$120 = 20 + x$.$x = 120 - 20 = 100 \ L$.Therefore,$100 \ L$ of water should be added.

In a mixture of $60 \ L$,the ratio of milk and water is $2:1$. What quantity of water (in $L$) should be added so that the ratio becomes $1:3$?

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