In a mole of water vapour at STP,the volume a | vedclass

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(B) The density of liquid water is $1 \,g/cc$. Therefore,$1 \,mol$ of water $(18 \,g)$ occupies an actual volume of $18 \,cc$.At $STP$,$1 \,mol$ of wa

Vedclass · Accepted Answer

Less than $1\%$ of $22.4 \,L$

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(B) The density of liquid water is $1 \,g/cc$. Therefore,$1 \,mol$ of water $(18 \,g)$ occupies an actual volume of $18 \,cc$.At $STP$,$1 \,mol$ of water vapour occupies a total volume of $22400 \,cc$ $(22.4 \,L)$.The percentage of volume actually occupied by the molecules is calculated as: $\frac{18 \,cc}{22400 \,cc} 	imes 100 \approx 0.08\%$.Since $0.08\% < 1\%$,the correct option is $(B)$.

In a mole of water vapour at $STP$,the volume actually occupied or taken by the molecules (i.e.,Avogadro's No. $\times$ Volume of one molecule) is

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