In an $npn$ transistor, $10^{10}$ electrons enter the emitter in $10^{-6} \; s$. If $4\%$ of the electrons are lost in the base, the current transfer ratio $(\alpha)$ will be:

  • A
    $0.98$
  • B
    $0.97$
  • C
    $0.96$
  • D
    $0.94$

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